Let F1, F2 be two foci of the ellipse and LT and LN be the tangent and the normal respectively to the ellipse at point L then
A
LN bisects ∠F1LF2
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B
LT bisects ∠F1LF2
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C
LT bisects angle (180∘−∠F1LF2)
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D
none of these
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Solution
The correct options are ALN bisects ∠F1LF2 BLT bisects angle (180∘−∠F1LF2)
Reflective property of ellipse: We know that the ray passing from F1 after reflecting at any point on ellipse passes through F2 i.e. the normal is angular bisector of ∠F1LF2.
i.e. LN bisects ∠F1LF2
So as the another angular bisector must be perpendicular to it, it is the tangent. So tangent bisects the external angle i.e. 180°−∠F1LF2.