CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
292
You visited us 292 times! Enjoying our articles? Unlock Full Access!
Question

Let f:[1,3]R be defined as

f(x)=|x|+[x], 1x<1x+|x|, 1x<2x+[x], 2x3

where [t] denotes the greatest integer less than or equal to t. Then, f is discontinuous at :

A
only one point
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
only two points
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
only three points
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
four or more points
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C only three points
f(x)=⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪x1, 1x<0x, 0x<12x, 1x<2x+2, 2x<3x+3, x=3

Clearly, we can see the function is discontinuous at x=0,1,3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Discontinuity
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon