CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

let f2 be the frequency of second line of Lyman series and f1 be the frequency of first line of Balmer series, then the frequency of first line of Lyman series is given by,

A
f2f1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
f2+f1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
f1f2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
f1f2f1+f2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A f2f1
For second line of Lyman series, f2=R c(112132) ___(1)
For first line of Balmer series,
f1=R c(122132) ___(2)
Subtracting (2) from (1) we get,
f=R c(112122)
The above equation gives the frequency of the first member of Lyman series.
f=f2f1

Hence, (A) is the correct answer.

Why this question?This question is based on the spectral line of hydrogen atom.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Planck's Quantum Hypothesis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon