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Question

Let, f:AB be an invertible function. If f(x)=2x3+3x2+x1, then f1(5)=

A
113
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B
1
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C
6
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D
can not be determined
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Solution

The correct option is A 113
Given f be an invertible function and f(x)=2x3+3x2+x1.
Then f1(5)=1f(x)xf(A) such that f(x)=5.
Now, f(x)=5 given only x=1 a real root, remaining are imaginary.
Now, f(x)=6(x2+x)+1.
f1(5)=1f(1)=113

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