wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f:AB be a function defined as f(x)=x1x2, where A=R{2} and B=R{1}. Then f is :

A
invertible and f1(y)=3y1y1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
invertible and f1(y)=2y1y1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
invertible and f1(y)=2y+1y1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Not invertible
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C invertible and f1(y)=2y1y1

As you can see that it is satisfying the domain conditions perfectly that is not containing {2} and we have to check whether the range which becomes a domain for the inverse also satisfies or not.

y=f(x)

x=f1(y)

y=x1x2=1+1x2

x=2+1y1=2y1y1

you can see that range also satisfies the condition that is not containing {1}.So we can say that is invertible.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Animal Tissues
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon