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Question

Let f:[α,)[x,),f(x)=x26x+5 then find three possible value of α if f(x) is onto.

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Solution

f(x)=x26x+5
By graph we can say xϵ[3,) then,
f(x)ϵ[4,)
when xϵ[5,) then f(x)ϵ[0,)
Possible value of α only 3&5

1039471_1015801_ans_f69fa40f73b94d40a765382fd62ac2bc.png

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