Let f and g be two differentiable functions on R such that f′(x)>0 and g′(x)<0, for all xϵR. Then for all x :
A
f(g(x))>f(g(x−1))
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B
f(g(x))>f(g(x+1))
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C
g(f(x))>g(f(x−1))
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D
g(f(x))<g(f(x+1))
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Solution
The correct option is Af(g(x))>f(g(x+1)) Let f(x)=ax g(x)=−bx where a, b > 0 f(g(x))⇒−abx ....(1) f(g(x+1))⇒a(−b−bx) =−abx−ab .....(2) . So, from (1) and (2) f(g(x))>f(g(x+1))