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Question

Let f and g be two differentiable functions on R such that f(x)>0 and g(x)<0, for all xϵR. Then for all x :

A
f(g(x))>f(g(x1))
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B
f(g(x))>f(g(x+1))
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C
g(f(x))>g(f(x1))
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D
g(f(x)) <g(f(x+1))
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Solution

The correct option is A f(g(x))>f(g(x+1))
Let f(x)=ax
g(x)=bx
where a, b > 0
f(g(x))abx ....(1)
f(g(x+1))a(bbx)
=abxab .....(2) .
So, from (1) and (2)
f(g(x))>f(g(x+1))

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