Let f be a function satisfying 2f(x)−3f(1x)=x2 for any x≠0, then the value of f(2) is
A
-2
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B
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C
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D
4
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Solution
The correct option is B 13(x2+4x−3)2f(x)−3f(1x)=x2……(i)Replacingxby1x2f(1x)−3f(x)=1x2……(ii) Solving (i) and (ii) we get −5f(x)=2x2+3x2f(x)=−15(2x2+3x2)∴f(2)=−15(8+34)=−74