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Question

Let f be a function satisfying f(x+y)=f(x)+f(y) for x,yϵR. If f(1)=k then f(n),nN, is equal to

A
kn
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B
nk
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C
nk
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D
None of these
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Solution

The correct option is B nk
Let f(x)=λ(x) where λ is a constant.

Hence

f(x+y)

=λ(x+y)

=λ(x)+λ(y)

=f(x)+f(y)

Now it has been given that f(1)=k

Therefore

λ=k

Hence

f(x)=k(x)

Therefore f(n)

=k(n)

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