Let f be a positive function. LetI1=∫k1−kxf{x(1−x)}dxI2=∫k1−kf{x(1−x)}dxwhere 2k−1>0. Then I1I2
Let f be a positive function. Let I1=∫k1−k xf{x(1−x)}dx, I2=∫k1−kf{x(1−x)}dx when 2k−1>0. Then I1I2 is [IIT 1997 Cancelled]