Let f be a real valued function satisfying f(x)+f(x+4)=f(x+6)+f(x+2) then ∫x+8xf(z)dz is a/an
A
constant function
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B
an odd function
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C
an even function
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D
periodic function
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Solution
The correct options are A constant function C an even function D periodic function f(x)+f(x+4)=f(x+2)+f(x+6) Substitute x=x+2 f(x+2)+f(x+6)=f(x+4)+f(x+8)⇒f(x)=f(x+8) Let g(x)=∫x+8xf(t)dt ⇒g′(x)=f(x+8)−f(x)=0 ⇒g(x) is a constant function