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Question

Let f be an even periodic function with period 2 and f(x)=xx[0,1]. Then f(3.14) equals

A
3.14
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B
0.14
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C
0.14
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D
0.86
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Solution

The correct option is D 0.86
f(x)=xforallxϵ[0,1]fbeaperiodof2.f(x+2)=x=f(x+4),xϵ[0,1]f(3.14)=f(40.86)=f[(2×2)+(0.86)]=0.86[becausef(x)=f(x)]

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