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Question

Let f be an invertible real function. Write

f-1 of 1 +f-1 of 2+...+f-1of 100.

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Solution

Given that f is an invertible real function.
f-1o f=I,where I is an identity function.So,f-1o f1+f-1o f2+...+f-1o f100=I1+I2+... +I100=1+2+...+100 As Ix=x, xR=100100+12[Sum of first n natural numbers=nn+12]=5050

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