Let f be the differentiable for all x, If f(1)=−2 and f′(x)≥2 for [1,6], then:
A
f(6)<8
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B
f(6)≥8
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C
f(6)=5
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D
f(6)<5
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Solution
The correct option is Bf(6)≥8 Let if possible f′(x)=2 for ⇒f(x)=2x+c (Integrating both side w.r.t. x) ∴f(1)=2+c,−2=2+c ⇒c=−4∴f(x)=2x−4 ∴f(6)=2×6−4=8∴f(6)≥8