RHL=limh→of(x+h)
RHL=limh→of(o+h)=limh→o(cos2h−sin2h−1√h+1−1)=limh→o(1−sin2h−sin2h−1√h+1−1)⋅(√h+1+1√h+1+1)=limh→o(−2sin2h(√h+1+1)h+1−1)=limh→o−2((sinhh)sinh(√h+1+1))
=−2⋅1⋅0⋅2=0∴forcontinuityLHL=RHL=f(0)∴k=0
Is the function f defined by
continuous at x = 0? At x = 1? At x = 2?