Let f:IR→IR be defined as f(x)=|x|+∣∣x2−1∣∣.The total number of points at which f attains either a local maximum or local minimum is
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Solution
Using Graph we have to check the nature of graph, f(x)=|x|+∣∣x2−1∣∣=|x|+|x−1||x−1| on the interval (−∞,−1);(−1,0);(0,1);(1,∞).The graph follows, Clearly we can see that there are 2 points of local maximum and 3 local minimum i.e total 5 points.