Let f is a continuous function for all x∈R and f(x)=f(x+2T),T>0. If I=2T∫0f(x)dx, then 4+40T∫4f(x4)dx is equal to
A
5I
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B
10I
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C
20I
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D
40I
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Solution
The correct option is C20I As, f(x)=f(x+2T);f(x) has period 2T
Now, Let I1=4+40T∫4f(x4)dx
Put x=4y,dx=4dy ⇒I1=41+10T∫1f(x)dx=4×52T∫0f(x)dx∵a+nT∫af(y)dy=nT∫0f(y)dy ∴I1=20I