Let fx-y-2-fx-fy-2 and f10 and f0-b then f1x is equal to

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Derivative of Some Standard Functions

Let fx+y/2=fx...

Question

Let $f (\frac{x + y}{2}) = \frac{f (x) + f (y)}{2}$ and $f^{1} (0)$ and $f (0) = b$ then $f^{1} (x)$ is equal to

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a+b

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Let $f (\frac{x + y}{2}) = \frac{f (x) + f (y)}{2}$ and $f^{1} (0)$ and $f (0) = b$ then $f^{1} (x)$ is equal to

f (\frac{x + y}{2}) = \frac{1}{2} [f (x) + f (y)]

f^{'} (0)

- 1

f (0) = 1

f (2)

f (\frac{x + y}{2}) = \frac{f (x) + f (y)}{2}

f^{'} (0) = 3

f (0) = 5

f^{''} (x)

y

x

f (x)

f : R \to R

f (\frac{x + y}{2}) = \frac{f (x) + f (y)}{2}

f (0) = 3

f^{'} (0) = 3

x, y ϵ R

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