The correct option is
B If
x≠1/2 then
f(x)<100Coefficient of of highest degree term must be negative because if it is positive, then
x→∞,y→∞ and it is not possible, since f(x)
≤ 100.
∴ option (A) is correct.
as x→∞, f(x)→−∞ and at x=1/2, f(x)=100 and as x→−∞,f(x)→−∞
∴ there exist at least one root in (−∞,1/2), and (1/2,∞)
∴ option (B) is correct.
consider the function f(x)=100−(x−1/2)2(x+1/2)2
observe that f(1/2)=100 and f(−1/2)=100
∴ option (C) need not be correct
Now, let the highest coefficients, it can have is 49.
then, f(1/2)=49+4922+4923+...
but the sum cannot be equal to 100
∴ there should be at least one coefficient greater than 50 in order to satisfy the above conditions.
∴ option (D) is correct.