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Question

Let f(x)=kcosxπ2xwhenxπ23x=π2 and if limxπ2f(x)=f(π2).
find the value of`k.

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Solution

f(x)=kcosxπ2x, when xπ2
=3 when x=π2

Now limxπ2f(x)=3

limxπ2f(x)=Kcosxπ2x=3

Now limxπ2f(x)|00 from

limxπ2f(x)| Applying L' Hospitalize Rule

=K2=K2

K2=3

K=6

K=6

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