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Question

Let f(x)=ecos1sin(x+π/3) Then

A
f(8π9)=e5π/18
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B
f(8π9)=e13π/18
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C
f(7π4)=eπ/12
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D
f(7π4)=e11π/12
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Solution

The correct option is B f(8π9)=e13π/18
f(x)=ecos1(sin(x+π3))
Now, f(8π9)=ecos1sin(11π9)
=ecos1cos(13π18)
=e(13π18)

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