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Question

Let f(x)=x3+ax2+bx+5sin2x be an increasing function in the in the set of real numers R.Then a and b satisfy the condition.

A
a23b15>0
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B
a23b+15
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C
a2+3b15<0
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D
a>0 & b>0
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Solution

The correct option is C a23b15>0
f(x)=x3+ax2+bx+5sin2x

Given that f(x) is incresing on R

Therefore, f(x)0

f(x)=3x2+2ax+b+10sinxcosx

f(x)=3x2+2ax+b+5sin2x0

For roots to exist, Δ0

Thereore, (2a)24(3)(b+5sin2x)0

4a24(3)(b+5sin2x)0

a23b15sin2x0

Maximum value of sin2x=1

Therefore,a23b150

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