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Question

Let f(x)=xsinx and g(x)=f(x)f(x),then number of distinct real roots of equation g(x)=0 where xϵ(2π,2π)is

A
5
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B
6
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C
7
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D
8
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Solution

The correct option is C 7
Given f(x)=xsinx

f(x)=xcosx+sinx

g(x)=xsinx(xcosx+sinx)

g(x)=0xsinx(xcosx+sinx)=0

xsinx=0 or tanx=x

(1)xsinx=0x={π,0,π}

(2)tanx=x

To solve above equation, draw tanx graph and y=x graph in the interval (2π,2π) and find out number of intersections

We get 5 intersections for above (see diagram)

Here '0' is a repeated value in both cases

total solutions =3+4=7

927805_129643_ans_36c5d21396264acd80f9c770a772fe95.png

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