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Question

Let
f(x,y)=∣ ∣ ∣yx2xy2xy1xy2xy1yx2xy1yx2xy2∣ ∣ ∣
find f(2,2).

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Solution

f(x,y)=∣ ∣ ∣yx2xy2xy1xy2xy1yx2xy1yx2xy2∣ ∣ ∣
f(2,2)=∣ ∣223232322∣ ∣

on expanding we get,

=20+2015=25

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