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Question

Let f:RR be a function defined by f(x)=x3+x2+3x+sinx. Then f is

A
injective and surjective
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B
injective but not surjective
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C
surjective but not injective
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D
neither injective nor surjective
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Solution

The correct option is A injective and surjective
f(x)=x3+x2+3x+sinx, xR
f(x)=3x2+2x+3+cosx
f(x)=g(x)+cosx
g(x)>0 as D=436=32<0
Range of g is [D4a,)
i.e., range of g is [+3212,)=[83,)
Also, 1cosx1
f(x)>0
Hence, function f is strictly increasing.
f is injective.

limxf(x)=
and limxf(x)=
Also, f is continuous over R.
Range of f is R
f is surjective.

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