The correct option is A injective and surjective
f(x)=x3+x2+3x+sinx, x∈R
f′(x)=3x2+2x+3+cosx
f′(x)=g(x)+cosx
g(x)>0 as D=4−36=−32<0
Range of g is [−D4a,∞)
i.e., range of g is [+3212,∞)=[83,∞)
Also, −1≤cosx≤1
∴f′(x)>0
Hence, function f is strictly increasing.
⇒f is injective.
limx→∞f(x)=∞
and limx→−∞f(x)=−∞
Also, f is continuous over R.
⇒ Range of f is R
∴f is surjective.