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Other
Quantitative Aptitude
A+B+C=N (N Fixed)
Let f:ℝ → ℝ b...
Question
Let
f
:
R
→
R
be defined by
f
(
x
)
=
1
x
∀
x
∈
R
.
Then
f
is
A
onto
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B
bijective
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C
f
is not defined
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D
one-one
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Solution
The correct option is
C
f
is not defined
Check existence of function.
Given:
f
:
R
→
R
,
f
(
x
)
=
1
x
Put
x
=
0
⇒
f
(
0
)
=
1
0
=
∞
So,
f
(
x
)
is not defined at
x
=
0
But in the question the domain given is
R
Hence, Option (d) is correct one.
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0
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A+B+C=N (N Fixed)
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