Let f:R→R and g:R→R be two bijective functions such that they are the mirror images of each other about the line y=a. If h:R→R given by h(x)=f(x)+g(x), then h(x) is
A
Neither a one-one nor an onto function
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
an onto but not a one-one function
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a one-one but not an onto function
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a one-one and an onto function
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Neither a one-one nor an onto function y=f(x) and y=g(x) are mirror image of each other about line y=a
Let for some x=b,g(b)−a=a−f(b) ⇒f(b)+g(b)=2a
So, we have h(b)=f(b)+g(b)=2a (constant)
Hence h(x) is a constant function.
Thus h:R→R is neither a one-one nor an onto function.