Let f:R→Z be a continuous function such that f(9)=3. Then the value of f(25)−f(1) is
A
4
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B
3
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C
cannot be determined
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D
0
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Solution
The correct option is D0 As f is continuous in R and can give only integral value, so f(x) is a constant function. f(x)=p (say)
As f(9)=3, so f(x)=3 ∴f(25)−f(1)=0