The correct option is
A Many-one and onto
By substituting values of
n, the elements in the range of function are,
{1,2,3,4,5,6,...............}, i.e. set of all natural number
So the range and co-domain are same, ergo function is onto.
Also f(1)=f(2), so the function is many one.
Hence the given function is many-one and onto