Question

Let $f:N\to R$ such that $f\left(x\right)=\frac{2x-1}{2}$ and $g:Q\to R$ such that $g\left(x\right)=x+2$ be two function. Then $\left(gof\right)\left(\frac{3}{2}\right)$ is equal to

• A. $3$
• B. $\frac{7}{2}$
• C. $1$
• D. $noneofthese$

Answer 1

Answer: (C)

$1$

We have,

$f\left(x\right)=\frac{2x-1}{2}$

$g\left(x\right)=x+2$

Since,

$\left(gof\right)\left(\frac{3}{2}\right)=g\left(f\left(\frac{3}{2}\right)\right)$

$f\left(\frac{3}{2}\right)=\frac{3-1}{2}=1$

Option $A$ is correct answer.