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Question

Let f : R -{35} R be a function defined by f(x) = 2x5x+3 find f1 (x)

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Solution

It is given that
f:R{3/5}R
and, f(x)=2x5x+3
Let f(x)=y. Then,
f(x)=y2x5x+3=y
2x5xy=3y
x(25y)=3y
x=3y
(25y)
Thus, f1 is given by f1(x)=3x(25x), forall xR{25}

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