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Question

Let f:R{x}R be a function defined by f(x)=xmxn, where mn. Then

A
f is one-one onto
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B
f is one-one into
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C
f is many one onto
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D
f is many one into
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Solution

The correct option is B f is one-one into
For any x,yR, we have
f(x)=f(y)
xmxn=ymyn
x=y
So, f is one-one.
Let αϵR such that f(x)=α
xmxn=α

x=mnα1α
Clearly, xR for α=1.
So, f is not onto.

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