Let f-R-R be defined as fx - 10x - 7- The function g-R-R such that gof - fog -IR- Then g2017 -

We have, nbsp;fog = nbsp;IR ⇒fog (x)= nbsp;IR(x) for all x nbsp;∈R ⇒fgx=x⇒10gx+7=x⇒gx=x 710∴g2017=2017 710=201 nbsp; ...

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How to Find the Inverse of a Function

Let f:R→R be ...

Question

Let $f : R \to R$ be defined as f(x) = 10x + 7. The function $g : R \to R$ such that gof = fog = $I_{R}$ . Then g(2017) =

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f : R \to R

g : R \to R

I_{R}

f : R \to R

f (x) = 10 x + 7

g : R \to R

g o f = f o g = I_{R}

Let $f : R \to$ be defined as f(x) =10x +7. Find the function $g : R \to R$ such that gof =fog = $I_{R}$ .

Let $f : R \to R$ be defined as $f (x) = 10 x + 7$ find the function $g : R \to R$ such that $g \cdot f = f \cdot g = I_{R}$

f : R \to R

f (s) = 10 x + 7

g : R \to R

g o f = f o g = 1_{R}

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