Let f : R → R be defined as f ( x ) = x 4 . Choose the correct answer. (A) f is one-one onto (B) f is many-one onto (C) f is one-one but not onto (D) f is neither one-one nor onto
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Solution
The given function f:R→R is defined by f(x)=x4.
Assume x,y∈R such that, f(x)=f(y).
⇒x4=y4⇒x=±y
It can be observed that f(x)=f(y) does not implies x=y. So, f is not one-one.
Let, −5 be an element in co-domain R. There does not exist any element x in the domain R such that, f(x)=−5.
So, f is not onto.
The function f:R→R , defined by f(x)=x4 is neither one-one nor onto.