Let f- - be the function defined by fx-4 x-3 for all x - Then write f-1- -NCERT EXEMPLAR-

We have, f nbsp;: nbsp;R nbsp; #8594; nbsp;R nbsp;is the function defined by nbsp;f(x) = 4x nbsp; nbsp;3 for all nbsp;x nbsp; #8712; ...

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Standard XII

Mathematics

Integration by Partial Fractions

Let f: 𝐑→𝐑 ...

Question

Let f : R $\to$ R be the function defined by f(x) = 4x $-$ 3 for all x $\in$ R. Then write f ^{$-$ 1}. [NCERT EXEMPLAR]

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Solution

We have,
f : R $\to$ R is the function defined by f(x) = 4x $-$ 3 for all x $\in$ R

$Let f (x) = y . Then, y = 4 x - 3 \Rightarrow 4 x = y + 3 \Rightarrow x = \frac{y + 3}{4} So, f^{- 1} (y) = \frac{y + 3}{4} or, f^{- 1} (x) = \frac{x + 3}{4}$

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Let f : R → R be the function defined by f(x) = 4x - 3 for all x ∈ R. Then write f -1. [NCERT EXEMPLAR]

We have, f : R → R is the function defined by f(x) = 4x - 3 for all x ∈ R Let fx=y. Then,y=4x-3⇒4x=y+3⇒x=y+34So, f-1y=y+34or, f-1x=x+34

Let f : R $\to$ R be the function defined by f(x) = 4x $-$ 3 for all x $\in$ R. Then write f ^{$-$ 1}. [NCERT EXEMPLAR]

We have,
f : R $\to$ R is the function defined by f(x) = 4x $-$ 3 for all x $\in$ R

$Let f (x) = y . Then, y = 4 x - 3 \Rightarrow 4 x = y + 3 \Rightarrow x = \frac{y + 3}{4} So, f^{- 1} (y) = \frac{y + 3}{4} or, f^{- 1} (x) = \frac{x + 3}{4}$