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Question

Let f:R[1,) be defined as f(x)=log10(3x24x+k+1+10). If f(x) is surjective, then

A
k=13
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B
k<13
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C
k>13
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D
k=1
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Solution

The correct option is A k=13
Range of F(x)=cos domain =[1,)log10(3x24x+k+1+10)13x24x+k+1+10103x24x+k+10D0




D016y(3)(k+1)01612k+(12)0412kk13k=1/3 Hence, (A) is the correct option


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