wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

Let f:RR and g:RR be continuous functions, then the value of π2π2(f(x)+f(x))(g(x)g(x))dx, is equal to

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0
Let I=π2π2(f(x)+f(x))(g(x)g(x))dx ...(1)
Using property baf(x)dx=baf(a+bx)dx
I=π2π2(f(x)+f(x))(g(x)g(x))dx ...(2)
Adding (1) and (2), we get
2I=π2π2(f(x)+f(x))((g(x)g(x))+(g(x)g(x)))dx=0I=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon