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Question

Let f:RR be a differentiable function satisfying f(x+y3)=2+f(x)+f(y)3x,yR and f(2)=2, then answer the following questions:
The range of g(x)=fx2 is

A
[1,)
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B
[2,)
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C
[0,)
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D
None of these
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Solution

The correct option is B [2,)
Substitute x=3x,y=0 in f(x+y2)=2+f(x)+f(y)3, we get
f(3x+03)=2+f(3x)+f(0)3f(x)=2+f(3x)+f(0)3 ...(1)
Substitute x=y=0
f(0)=2+f(0)+f(0)33f(0)=2+2f(0)f(0)=2 ....(2)
From (1)
f(x)=2+f(3x)+233f(x)=f(3x)+4 ...(3)
Now f(x)=limh0f(x+h)f(x)h=limh0f(3x+3h3)f(x)h

=limh0⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪2+f(3x)+f(3h)3f(x)h⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪=limh0[2+f(3x)+f(3h)3f(x)3h]

=limh0[2+3f(x)4+f(3h)3f(x)3h]
f(x)=limh0[f(3h)23h]
Since f(x) is differentiable x;limh0f(3h)=2
f(0)=2f(x)=limh03f(3h)3=f(0)=k (say)
f(x)=kf(x)=kx+c
f(x)=kf(2)=k
But f(2)=2k=2
f(x)=2x+c
Also f(0)=2c=2
f(x)=2x+2
f(|x|)=2|x|+2
f(x2)=2x2+2=|x|+2;
g(x)=fx2=||x|+2|=|x|+2{x+2x0x+2x<0
Graph of ||x|+2| is shown below
Clearly the range of g(x) is [2,)

399695_131066_ans.PNG

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