Let f:R→R be a function defined as f(x)=x2+2x+5x2+x+1. Then f is
A
One-one and into
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B
One-one and onto
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C
Many-one and into
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D
Many-one and onto
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Solution
The correct option is C Many-one and into x2+x+1>0,x2+2x+5>0⇒f(x)>0 ⇒ f is into as range is not R f′(x)=(x2+x+1)(2x+2)−(x2+2x+5)(2x+1)(x2+x+1)2 f'(x) = 0 has real roots so f is many-one