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Question

Let f:RR be defined by f(x)=x+2x1x21<x<12xx1 then the value of f(1.75)+f(0.5)+f(1.5) is

A
0
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B
2
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C
1
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D
1
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Solution

The correct option is C 1
f(x)=x+2x1x21<x<12xx1
f(175)=175+2
=25
f(05)=052
=025
f(15)=2(15)
=05
f(175)+f(05)+f(15)=1

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