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Question

Let f(θ)=sinθ(sinθ+sin3θ), then f(θ)

A
≥ 0 only when θ≥ 0
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B
≤ 0 for all real θ
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C
≥ 0 for all real θ
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D
≤ 0 only when θ ≤0
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Solution

The correct option is C ≥ 0 for all real θ

Here, f(θ)=sinθ(sinθ+sin3θ)

=sinθ(sinθ+3sinθ4sin3θ)=4sin2θ(1sin2θ)

=4sin2θcos2θ=(sin2θ)2

f(θ)0 for all real θ.


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