No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
≤0forallralθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
≥0forallrealθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
≤0onlywhenθ≤0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C≥0forallrealθ f(θ)=sinθ(sinθ+sin3θ)=(sinθ+3sinθ−4sin3θ).sinθ=(4sinθ−4sin3θ)sinθ=sin2θ(4−4sin2θ)=4sin2θ(1−sin2θ)=4sin2θcos2θ=(2sinθcosθ)2=(sin2θ)2≥0\\ which is true for all θ.