Question

Let $f(x+1)=2x^2-3x+1$ then find the value of $f(x+2)$.

Answer 1

Given $f(x+1)=2x^2-3x+1$ ……..$\left(1\right)$

Now, to find $f(x+2)$ let us

put $(x+1)$ in place of 'x' in $\left(1\right)$

or, $f(x+2)=2(x+1{)}^2-3(x+1)+1$

$=2(x^2+2x+1)-3(x+1)+1$

$=(2x^2+x)$.