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Byju's Answer
Standard XII
Mathematics
Composite Function
Let fx = 21...
Question
Let
f
(
x
)
=
2
100
x
+
1
g
(
x
)
=
3
100
x
+
1
Then the set of real numbers x such that
f
(
g
(
x
)
)
=
x
is
A
Empty
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B
A singleton
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C
A finite se with more than one element
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D
Infinite
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Solution
The correct option is
B
A singleton
f
(
g
(
x
)
)
=
2
100
(
3
100
x
+
1
)
+
1
=
x
⇒
x
(
6
100
−
1
)
=
−
(
1
+
2
100
)
Clearly there is just one of value of x satisfying this equation. Option B is correct.
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Similar questions
Q.
If
f
(
x
)
=
2
100
x
+
1
,
g
(
x
)
=
3
100
x
+
1
, then the set of real numbers
x
such that
f
{
g
(
x
)
}
=
x
is
Q.
Let
f
(
x
)
=
x
1
+
x
and
g
(
x
)
=
r
x
1
−
x
. Let
S
be the set of all real numbers
r
such that
f
(
g
(
x
)
)
=
g
(
f
(
x
)
)
for infinitely many real
x
. The number of elements in set
S
is
Q.
Let
R
be the set of real numbers and the functions
f
:
R
→
R
and
g
:
R
→
R
be defined by
f
(
x
)
=
x
2
+
2
x
−
3
and
g
(
x
)
=
x
+
1
. Then the value of
x
for which
f
(
g
(
x
)
)
=
g
(
f
(
x
)
)
is
Q.
Let f(x) = x
2
and g(x) = 2x+ 1 be two real functions. Find (f + g) (x), (f − g) (x), (fg) (x) and
f
g
x
.
Q.
Suppose that
g
(
x
)
=
1
+
√
x
and
f
(
g
(
x
)
)
=
3
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√
x
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, then
f
(
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is
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