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Question

Let f(x)=2100x+1
g(x)=3100x+1
Then the set of real numbers x such that f(g(x))=x is

A
Empty
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B
A singleton
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C
A finite se with more than one element
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D
Infinite
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Solution

The correct option is B A singleton
f(g(x))=2100(3100x+1)+1=x

x(61001)=(1+2100)

Clearly there is just one of value of x satisfying this equation. Option B is correct.

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