Question

Let $f\left(x\right)=2x^3+x^2+x+4$, find the remainder when $f\left(x\right)$ is divided by $(x-1)$.

Answer 1

Given, $f\left(x\right)=2x^3+x^2+x+4$.

Now using remainder theorem when $f\left(x\right)$ is divided by $(x-1)$ we have the remainder is $f\left(1\right)$.

Now,

$f\left(1\right)=2+1+1+5=8$.

So the remainder is $8$.