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Question

Let f(x)=(axn)1n,a>0 and n is positive integer, then prove that f[f(x)]=x.

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Solution

Given f(x)=(axn)1n for a>0 and n is positive integer.
Now
f[f(x)]
=[a{(axn)1n}n]1n
=[aa+xn]1n=x

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