Let f(x)=ax2+bx+c and g(x)=Ax2+bx+λ, where a≠0,A≠0,a,b,c,A,λ∈R. Roots of f(x)=0 and g(x)=0 are imaginary, then which of the following may be correct?
A
f(x)+g(x)=0 for some x
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B
f(x)a+g(x)A>0∀x∈R
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C
f(x)a+g(x)A>0 for some x
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D
Roots of equation af(x)+Ag(x)=0 are real
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Solution
The correct options are Af(x)+g(x)=0 for some x Bf(x)a+g(x)A>0∀x∈R f(x)=0 & g(x)=0 has imaginary roots So f(x)>0&g(x)>0∀x∈Rifa>0,A>0...(i) f(x)>0&g(x)<0∀x∈Rifa>0,A<0...(ii) f(x)<0&g(x)>0∀x∈Rifa<0,A>0...(iii) f(x)<0&g(x)<0∀x∈Rifa<0,A<0...(iv) f(x)+g(x)=0 for some x is correct in (ii) & (iii) case. Also, f(x)a and g(x)A>0∀x∈R, So f(x)a+g(x)A>0∀x∈R is also correct