Let f(x) be a continuous and increasing function on R and suppose F(x)=1+f(x)+f2(x)+f3(x).
If the equation F(x)=0 has a positive root, then:
A
F(x) is a decreasing function of x on R
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B
f(0)<−1
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C
f(0)>0
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D
|f(0)|<1
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Solution
The correct option is Bf(0)<−1 We have, F(x)=1+f(x)+f2(x)+f3(x) ⇒F(x)=(1+f(x))(1+f2(x)) F(x)=0⇒f(x)=−1 f(α)=−1 where αϵR+
So α>0 and as f(x) is an increasing function. f(α)>f(0)
So f(0)<−1