Let f(x) be a non-positive continuous function and F(x)=x∫0f(t)dt∀x≥0 and f(x)≥cF(x) where c>0 and let g:[0,∞)→R be a function such that dg(x)dx<g(x)∀x>0 and g(0)=0.
The solution set of inequality g(x)(cos−1x−sin−1x)≤0
A
[−1,1√2]
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B
[1√2,1]
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C
[0,1√2]
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D
(0,1√2]
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Solution
The correct option is A[−1,1√2] g(x)(cos−1x−sin−1x)≤0
or (cos−1x−sin−1x)≥0 or x∈[−1,1√2]